3[4(x-3)+1]=0

Solution for 3[4(x-3)+1]=0 equation:

Simplifying
3[4(x + -3) + 1] = 0

Reorder the terms:
3[4(-3 + x) + 1] = 0
3[(-3 * 4 + x * 4) + 1] = 0
3[(-12 + 4x) + 1] = 0

Reorder the terms:
3[-12 + 1 + 4x] = 0

Combine like terms: -12 + 1 = -11
3[-11 + 4x] = 0
[-11 * 3 + 4x * 3] = 0
[-33 + 12x] = 0

Solving
-33 + 12x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '33' to each side of the equation.
-33 + 33 + 12x = 0 + 33

Combine like terms: -33 + 33 = 0
0 + 12x = 0 + 33
12x = 0 + 33

Combine like terms: 0 + 33 = 33
12x = 33

Divide each side by '12'.
x = 2.75

Simplifying
x = 2.75